Overlapping of Atomic Orbitals
Overlapping of Atomic Orbitals
When two
atoms come close to each other, there is overlapping of atomic orbitals. This
overlap may be positive, negative or zero depending upon the properties of
overlapping of atomic orbitals. The various arrangements of s and p orbitals
resulting in positive, negative and zero overlap are depicted in below figure.
The
criterion of overlap, as the main factor for the formation of covalent bonds
applies uniformly to the homonuclear/heteronuclear diatomic molecules and
polyatomic molecules. In the case of polyatomic molecules like CH4,
NH3 and H2O, the VB theory has to account for their
characteristic shapes as well. We know that the shapes of CH4, NH3
and H2O molecules are tetrahedral, pyramidal and bent respectively.
It would be therefore interesting to find out if these geometrical shapes can
be explained in terms of the orbital overlaps.
Let us first
consider the CH4 (methane) molecule. The electronic configuration of
carbon in its grounds state is ⦗He⦘2s2 2p2
which in the excited state becomes ⦗He⦘2s1 2px1
2py1 2pz1. The energy
required for this excitation is compensated by the release of energy due to
overlap between the orbitals of carbon and the hydrogen. The four atomic
orbitals of carbon, each with an unpaired electron can overlap with the 1s
orbitals of the four H atoms which are also singly occupied. This will result
in the formation of four C-H bonds. It will, however, be observed that while
the three p orbitals of carbon
are at 90 to one another , the HCH angle for these will also be 90. That is
three C-H bonds will be oriented at 90 to one another. The 2s orbital of
carbon and the 1s orbital of H are spherically symmetrical and they can
overlap in any direction. Therefore the direction of the fourth C-H bond cannot
be ascertained. This description does not fit in with the tetrahedral HCH
angles of 109.5. Clearly, it follows that simple atomic orbital overlap does not
account for the directional characteristics of bonds in CH4. Using
similar procedure and arguments, it can be seen that in the case of NH3
and H2O molecules, the HNH and HOH angles should be 90. This is in
disagreement with the actual bond angles of 107 and 104.5 in the NH3
and H2O molecules respectively.
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