Types of Hybridization

Types of Hybridization

There are various types of hybridization involving s, p, and d orbitals. The different types of hybridization are as under.

sp hybridization: 

This type of hybridization involves the mixing of one s and one p orbital resulting  in the formation of two equivalent sp hybrid orbitals. The suitable orbitals for sp hybridization are s and pz, if the hybrid orbitals are to lie along the z-axis. Each sp hybrid orbitals has 50% s-character and 50% p-character. Such a molecule in which the central atom is sp-hybridized and linked directly to two other central atoms possesses liner geometry. This type of hybridization is also known as diagonal hybridization.

The tow sp hybrids point in the opposite direction along the z-axis with projecting positive lobes and very small negative lobes, which provides more effective overlapping resulting in the formation of stronger bonds.

Example of molecule having sp hybridization

BeCl₂: The ground state electronic configuration of Be is 1s²2s². In the exited state one of the 2s-electrons is promoted to vacant 2p orbital to account for its divalency. One 2s and one 2p-orbitals get hybridized to form two sp hybridized orbitals. These two sp hybrid orbitals are oriented in opposite direction forming an angle of 180. Each of the sp hybridized orbital overlaps with the 2p-orbital of chlorine axially and form two Be-Cl sigma bonds. This is shown below figure.

 Sp² hybridization :

 In this hybridization there is involvement of one s and two p-orbitals in order to form three equivalent sp² hybridized orbitals. For example, in BCl₃ molecule, the ground state electronic configuration of central boron atom is 1s²2s²2p¹. In the excited state, one of the 2s electrons is promoted to vacant 2p orbitals as a result boron has three unpaired electrons. These three orbitals (one 2s and two 2p) hybridise to form three sp² hybrid orbitals. The three hybrid orbitals so formed are oriented in a trigonal planar arrangement and overlap with 2p orbitals of chlorine to form three B-Cl bonds. Therefore, in BCl₃ the geometry is trigonal planar with CIBCl bond of 120.

Sp³ hybridization: 

This type of hybridization can be explained by taking the example of CH₄ molecule in which three is mixing of one s-orbital and three p-orbitals of the valence shell to form four sp³ hybrid orbital of equivalent energies and shape. There is 25% s-character and 75% p-character in each sp³ hybrid orbital. The four sp³ hybrid orbitals so formed are directed towards the four corners of the tetrahedron. The angle between sp³ hybrid orbital is 109.5 as shown below.

The structure of NH₃ and H₂O molecules can also be explained with the help of sp³ hybridization.  In NH₃, the valence shell (outer) electronic configuration of nitrogen in the grounds state is 2s²  2p¹_x  2p¹_y  2p¹_z having three unpaired electrons in the sp³ hybrid orbitals and a lone pair of electrons is present in the fourth one. These three hybrid orbitals overlap with 1s orbitals of hydrogen atoms to form three N-H sigma bonds.  As we know that the force of repulsion between a lone pair and a bond pair is more than the force of repulsion between two bond pairs of electrons. The molecule thus gets distorted and the bond angle is reduced to 107 from 109.5. The geometry of such a molecule will be pyramidal as shown below.

In the case of H₂O molecule, the four oxygen orbitals (one 2s and three 2p) undergo sp³ hybridization forming four sp³ hybrid orbitals out of which two contain one electron each and the other two contain a pair of electrons. These four sp³ hybrid orbitals acquire a tetrahedral geometry, with two corners occupied by hydrogen atoms while the other two by the lone pairs. The bond angle in this case is reduced to 104.5 from 109.5 and the molecule thus acquires a V-shape or angular geometry.